Question

Need this by tonight

Answer 1

`f(-1)=(-1)/(2)`

`g(-2)=(5)/(32)`

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

Explanation:

Step 1: Define

`f(x)=(2x-1)/(2x^3-8x)`

`g(x)=(2x-1)/(2x^3+8x)`

f(-1) is x = -1

g(-2) is x = -2

Step 2: Evalaute

f(-1)

1. Substitute:
   `f(-1)=(2(-1)-1)/(2(-1)^3-8(-1))`
2. Evaluate:
   `f(-1)=(2(-1)-1)/(2(-1)-8(-1))`
3. Multiply:
   `f(-1)=(-2-1)/(-2+8)`
4. Subtract/Add:
   `f(-1)=(-3)/(6)`
5. Divide:
   `f(-1)=(-1)/(2)`

g(-2)

1. Substitute:
   `g(-2)=(2(-2)-1)/(2(-2)^3+8(-2))`
2. Evaluate:
   `g(-2)=(2(-2)-1)/(2(-8)+8(-2))`
3. Multiply:
   `g(-2)=(-4-1)/(-16-16)`
4. Subtract:
   `g(-2)=(-5)/(-32)`
5. Simplify:
   `g(-2)=(5)/(32)`

And we have our final answers!