Question

A car starts from rest and is moving at 60.0 m/s after 7.50 s. What is the car's average acceleration?

Help!!!

Answer 1

`{ \boxed{ \bold{ \sf{Acceleration \: ( \: a) = 8 \: m/ {s \: }^(2) }}}}`

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♨ Question :

• A car starts from rest and is moving at 60.0 m/s after 7.50 s. What is the car's average acceleration ?

♨
`\underbrace{ \sf{Required \: Answer : }}`

☄ Given :

• Initial velocity ( u ) = 0
• Final velocity ( v ) = 60.0 m/s
• Time ( t ) = 7.50 s

☄ To find :

• Acceleration ( a )

✒ We know ,

`\boxed{ \underline{ \bold{ \sf{Acceleration \: ( \: a) = (Final velocity ( v ) - Initial velocity ( u))/(t) }}}}`

Substitute the values and solve for a.

➛
`\sf{a = (60.0 - 0)/(7.50)}`

➛
`\sf{a = (60.0)/(7.50)}`

➛
`\boxed{ \boxed{ \sf{a = 8 \: m/ {s \: }^(2) }}}`

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✑ Additional Info :

• When a certain object comes in motion from rest , in the case , initial velocity ( u ) = 0
• When a moving object comes in rest , in the case , final velocity ( v ) = 0
• If the object is moving with uniform velocity , in the case , u = v.
• If any object is thrown vertically upwards in the case , a = -g
• When an object is falling from certain height , in the case , final velocity at maximum height ( v ) = 0.

Hope I helped!

Have a wonderful time ツ

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