Let a, b, and c be constants, and let x be a variable. Which of the following is equivalent to a(x + b) < c when a < 0? (Rearranging Formulas) IMAGE BELOW :D

Question

asked Mar 16, 2021 112k views

1 Answer

Iris · Answer 1 · 2021-03-20T16:35:37+0000

Answer:

C

Explanation:

We are given that:

a(x+b)<c

Where a < 0.

To solve for x, we can divide both sides by a.

Since a < 0, a is negative. Hence, we must flip the inequality sign. This yields:

$\displaystyle x + b > (c)/(a)$

Subtract b from both sides. Hence:

$\displaystyle x>(c)/(a)-b$

In conclusion, our answer is C.