Question

Let a, b, and c be constants, and let x be a variable. Which of the following is

equivalent to a(x + b) < c when a < 0? (Rearranging Formulas) IMAGE BELOW :D

Answer 1

C

Explanation:

We are given that:

`a(x+b)<c`

Where a < 0.

To solve for x, we can divide both sides by a.

Since a < 0, a is negative. Hence, we must flip the inequality sign. This yields:

`\displaystyle x + b > (c)/(a)`

Subtract b from both sides. Hence:

`\displaystyle x>(c)/(a)-b`

In conclusion, our answer is C.