Question

Solve for x

`\bold{x^(2) + 6x + 5 = 0}`

ty! ~

Answer 1

`{x}^(2) + 6x + 5 = 0 \\ \\ {x}^(2) + 5x + x + 5 = 0 \\ \\ x(x + 5) + 1(x + 5) = 0 \\ \\ (x + 1)(x + 5) = 0.`

`x = - 1 \\ x = - 5.`

Answer 2

x²+6x+5=0

On comparing with the equation

ax² + bx + c = 0

a=1, b = 6 and c = 5

Now

b²– 4ac = 6² – 4 x 1 x 5 = 36 - 20 = 16

`x = \frac{ - b \:± \: \sqrt{b {}^(2) - 4ac } }{2a} \\ \\ x = ( - 6\:± \: √(16 ) )/(2 * 1) \\ \\ x = \frac{ - 6± {4} }{2} \\ \\ x = \frac{ - 6 + {4} }{2} \: \: or \: \: x = \frac{ - 6 - {4} }{2} \\ \\ \implies \: x = ( \cancel-2 )/( \cancel2)^(-1 )\: \: or \: \: x = ( \cancel-10 )/( \cancel2)^(-5)\\ \\ \implies \: { \blue{\fbox{ \: x = - 1 \: \: \: or \: \: \:x = - 5}}}`