Question

1.5 mol CaCO3 in 0.5 L solution. What is the molarity?

Answer 1

`\displaystyle \text{ 3 M}`

Step-by-step explanation:

Molarity is given by the ratio of the amount of moles of the solute over the total volume of the solution. That is:

`\displaystyle \text{M} = \frac{\text{ mols solute}}{\text{ L soln.}}`

Substitute:

`\displaystyle \begin{aligned} \text{M} & = \frac{(1.5\text{ mol CaCO$_3$} ) } { (0.5\text{ L soln.} )} \\ \\ & = 3\text{ M}\end{aligned}`

In conclusion, the solution is 3 molar.