Question

A force of 29.4 N is required to pull a 100 kg ice block at constant speed along an ice surface. Find the coefficient of kinetic friction for ice on ice.

Answer 1

The value is
`\mu_k = 0.03`

Step-by-step explanation:

From the question we are told that

The force applied on the ice is
`F = 29.4 N`

The mass of the ice block is
`m = 100 \ kg`

Generally for the ice block to move at constant speed , the force applied on it must be equal to the kinetic frictional force which is mathematically represented as

`F_F = m* g * \mu_k`

=>
`F = F_F = m* g * \mu_k`

=>
`29.4 = 100 * 9.8 * \mu_k`

=>
`\mu_k = 0.03`