Answer:
The answer is slightly above 0°C.
Step-by-step explanation:
The ice melts and absorbs 330 J/g × 100 g = 33000 joules.
Cooling 400 g of water from 25°C to 0°C requires
4 J/K-g × 400 g × 25°C = 40000 joules
The heat taken to melt is almost enough to cool the water all of the way to 0°C.
The answer is slightly above 0°C.