16.7k views
0 votes
Find the indicated values, where g(t)=t^2-t and f(x)=1+x g(f(2)+3)

User AntiMoron
by
5.4k points

1 Answer

5 votes

Answer:


g(f(2)+3)=30

Explanation:

We have the two functions:


g(t)=t^2-t\text{ and } f(x)=1+x

And we wish to find:


g(f(2)+3)

First, let’s find f(2) first. So, we will substitute 2 for x for f(x):


f(2)=1+(2)=3

Hence, we can now substitute 3 for f(2):


g(f(2)+3)=g(3+3)=g(6)

Now, we can find g(6). Substitute 6 for t for g(t):


g(6)=(6)^2-(6)=36-6=30

Therefore:


g(f(2)+3)=30

User Werolik
by
5.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.