16.7k views
0 votes
Find the indicated values, where g(t)=t^2-t and f(x)=1+x g(f(2)+3)

User AntiMoron
by
8.1k points

1 Answer

5 votes

Answer:


g(f(2)+3)=30

Explanation:

We have the two functions:


g(t)=t^2-t\text{ and } f(x)=1+x

And we wish to find:


g(f(2)+3)

First, let’s find f(2) first. So, we will substitute 2 for x for f(x):


f(2)=1+(2)=3

Hence, we can now substitute 3 for f(2):


g(f(2)+3)=g(3+3)=g(6)

Now, we can find g(6). Substitute 6 for t for g(t):


g(6)=(6)^2-(6)=36-6=30

Therefore:


g(f(2)+3)=30

User Werolik
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories