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Given

f(x) = 6x^3 +19x²-29x +c where c is a constant
if (x-1) is a factor of f(x),
find value of c
Hence, solve the equation of f(x) =0.

User SortingHat
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1 Answer

1 vote

Answer:


c=4\\x=1, x=(-25+√(721))/(12),x=(-25-√(721))/(12)

Explanation:

See the picture attached

Given f(x) = 6x^3 +19x²-29x +c where c is a constant if (x-1) is a factor of f(x), find-example-1
User M Soegtrop
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