Question

The specific heat of a certain type of metal is 0.128 J/(g⋅∘C). What was the intial temperature if 0.305 kJ of heat is added to 94.8 g of metal to reach a temperature of 85.0 ∘C?

Answer 1

The intial temperature : 59.865 °C

Further explanation

Heat added :

Q = m . c . ΔT

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

`\tt 305=94.8* 0.128* (85-t_1)\\\\85-t_1=25.135\\\\t_1=59.865^oC`