Question

In the reaction of Zn with HCl, 140.15 g of ZnCl2 was actually formed, although the theoretical yield

was 143 g. What was the percent yield?

Zn + 2HCl ➡ ZnCl2 + H2

Answer 1

Percent yield = 98%

Step-by-step explanation:

Given data:

Actual yield of ZnCl₂ = 140.15 g

Theoretical yield of ZnCl₂ = 143 g

Percent yield = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield )× 100

Percent yield = (140.15 g/ 143 g)× 100

Percent yield = 0.98 × 100

Percent yield = 98%