Question

a ball is rolling ar 4.80m/s over level ground when it encounters a ramp which gives it an acceleration of -0.875m/s^{2. if the ramp is 0.750m long, what is the final velocity of the ball when it reaches the top of the ramp?

Answer 1

4.66m/s

Step-by-step explanation:

Given parameters:

Initial velocity = 4.8m/s

Acceleration = -0875m/s²

Length of the ramp = 0.75m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we apply the right motion equation;

V² = U² + 2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance = length of ramp

Insert the parameters;

V² = 4.8² + 2(-0.875)0.75

V² = 23.04 - 1.31

V² = 21.73

V = √21.73 = 4.66m/s