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If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record your answer in scientific notation using 3 significant figures.

User Figolu
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1 Answer

6 votes

Answer:

3.43×10¹ mol

Step-by-step explanation:

Given data:

Initial number of moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁ = V₂/n₂

122.8 L/ 12.4 mol = 339.2 L / n₂

n₂ = 339.2 L× 12.4 mol / 122.8 L

n₂ = 4206.08 L.mol /122.8 L

n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

User Varma Mukesh
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