Answer:
The worth of boat in 2013 will be $9202.6
Explanation:
Rate of depreciation = 9% = 0.09
Cost of Boat in 2006 =$ 17,800
Cost of Boat in 2013 = ?
Years = 2013-2006= 7 years
The formula used is:
![\mathbf{A=P(1+r)^(t)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/j7j9arzfbf5e81nk6qmfu44c2yn6ud350f.png)
Since the value of boat is depreciating the value of r will be r=-0.09
Here P = 17,800 , r=-0.09 and t = 7 years Finding A
![A=P(1+r)^(t)\\A=17,800(1+(-0.09))^7\\A=17,800(0.91)^7\\A=17,800(0.517)\\A=9202.6](https://img.qammunity.org/2021/formulas/mathematics/high-school/9h1rhd5rsjxehqnhjmumkqm9rvf8ss67o5.png)
So, the worth of boat in 2013 will be $9202.6