Answer:
The circumference is 565.2 feet when the ferris wheel makes 4 rotations.
Explanation:
Given that the diameter of the wheel is 45 feet.
That is:
![d = 45\ feet](https://img.qammunity.org/2021/formulas/mathematics/college/mrkaw0bo5jqvaev0fvrpjzy1enzqsgygsl.png)
We have to find the radius first
![r = (d)/(2) = (45)/(2) = 22.5\ feet](https://img.qammunity.org/2021/formulas/mathematics/college/dvpsxfem7ianr76evzqwohcdslggjgtwfv.png)
The circumference of the circular wheel for one rotation will be:
![C = 2\pi r](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pmqp0wjx9ci5d9giffw44n8s69k92ypksg.png)
And for four rotations' circumference the circumference of one rotation will be multiplied with 4.
![C = 2 * 3.14 * 22.5\\C = 141.3\ feet](https://img.qammunity.org/2021/formulas/mathematics/college/textqlpssob6k9l1ef5ae6vvkm9f04iulw.png)
Total circumference:
Hence,
The circumference is 565.2 feet when the ferris wheel makes 4 rotations.