Answer:
After solving the equation
we get x=-2 and x= 4 i.e {-2,4}.
Option B is correct.
Explanation:
We need to solve

Solving:

Cross multiply

Multiplying:

Now, we have got quadratic equation

Solving this quadratic equation using quadratic formula

We have a=1, b=-2 and c=-8 Putting values

So,after solving the equation
we get x=-2 and x= 4 i.e {-2,4}.
Option B is correct.