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What is the center of the circle given by the equation (x-2)2+(y+4)2=6
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What is the center of the circle given by the equation (x-2)2+(y+4)2=6

User HjalmarCarlson
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1 Answer

6 votes

Answer:

(2,-4)

Explanation:

Here, h=2 and k=-4, so the center is (2,-4)

What is the center of the circle given by the equation (x-2)2+(y+4)2=6-example-1
User BlackSheep
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