Question

Two 5.0-kg carts collide on a one-dimensional air track. The total momentum of the carts was 4.9 kg m/s rightwards before the collision. After the collision, one cart is moving leftwards at 0.15 m/s. what is the velocity of the second cart?

Answer 1

Answer: 1.13 m/s equivalent to 1.1 m/s

Step-by-step explanation:

Answer 2

1.13 m/s right

Step-by-step explanation:

Momentum before = momentum after

p₀ = p

p₀ = m₁ v₁ + m₂ v₂

4.9 kg m/s = (5.0 kg) (-0.15 m/s) + (5.0 kg) v

4.9 kg m/s = -0.75 kg m/s + (5.0 kg) v

5.65 kg m/s = (5.0 kg) v

v = 1.13 m/s