Question

A person picking apples stand on a ladder 3.0 m above the ground. He throws them into

a basket 2.0 m away. How fast must the person throw the apple in order for it to land in
the basket?

Answer 1

The speed the apple must be thrown in order for it to land in the basket is 2.554 m/s.

Step-by-step explanation:

Given;

height above the ground, h = 3.0 m

horizontal distance, X = 2.0 m

The time to drop from the given height;

h = ¹/₂gt²

`t = \sqrt{(2h)/(g) }\\\\t = \sqrt{(2*3)/(9.8) }\\\\t = 0.783 \ s`

The horizontal speed traveled by the apple is given by;

vₓ = X / t

vₓ = 2 / 0.783

vₓ = 2.554 m/s

Therefore, the speed the apple must be thrown in order for it to land in the basket is 2.554 m/s.