Question

The midpoint of AB given A (3, -12) and B (-1, -2) is (x, y). What are the
values of x and y?

Answer 1

Explanation:

`x_(m) , y_(m) \: = ( (x _(1) + x_(2) )/(2) ,(y _(1) + y_(2) )/(2)) \\`

x1 = 3, x2 = (-1)

y1 = (-12), y2 = (-2)

`x_(m) , y_(m) \: = ( (3+ ( - 1) )/(2) ,(( - 12)+ ( - 2) )/(2)) \\`

`x_(m) , y_(m) \: = ( (3 - 1 )/(2) ,(( - 12) - 2 )/(2)) \\`

`x_(m) , y_(m) \: = ( (2 )/(2) ,(- 14 )/(2)) \\`

`x_(m) , y_(m) \: = 1 ,( - 7)`

Answer 2

(1, - 7 )

Explanation:

using the midpoint formula

given endpoints (x₁, y₁ ) and (x₂, y₂ ) , then

midpoint = (
`(x_(1)+x_(2) )/(2)` ,
`(y_(1)+y_(2) )/(2)` )

here (x₁, y₁ ) = A (3, - 12 ) and (x₂, y₂ ) = B (- 1, - 2 )

midpoint = (
`(3-1)/(2)` ,
`(-12-2)/(2)` ) = (
`(2)/(2)` ,
`(-14)/(2)` ) = (1, - 7 )