Question

Show solving steps for x^2-10x +4=12

Answer 1

Explanation:

We are given

`x^2 - 10x + 4 = 12\\`

get it all to one side equaling zero

`x^2 - 10x - 8 = 0`

now, we want to find the factors of 8 that either add up to of have a difference of 10

Factors of 8:

`1, 8, 2, 4`

None of the factor pairs add up to or have a difference of 10.

So, we can use the quadratic formula

`x = (-b\pm√(b^2-4ac) )/(2a) \\x = (10\pm√(100-4*8) )/(2)\\x = (10\pm√(132) )/(2)\\\\\\x = (10 + √(132) )/(2)= 10.74456265\\x = (10 - √(132) )/(2) = -0.7445626465`