Answer:
His initial velocity (speed) must be 64.16 m/s.
Step-by-step explanation:
Horizontal Motion
When an object is horizontally launched at a speed v from a height h, the maximum horizontal distance (also called Range) traveled by the object can be calculated as follows:
![\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}](https://img.qammunity.org/2021/formulas/physics/college/h2zuitzheyxmyce4ej5d2wtyr9navlusii.png)
Our daredevil is attempting to clear a river d=420 m wide with his motorcycle from a cliff h=210 m high. We need to find the speed needed to safely reach the opposite edge of the river.
From the above equation, we solve for v:
Speed:
![\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}](https://img.qammunity.org/2021/formulas/physics/high-school/7ne5n0j8ezkcymekbopg2nzevo9354r0t5.png)
![\displaystyle v=420\cdot\sqrt{\frac {9.8}{2\cdot 210}}](https://img.qammunity.org/2021/formulas/physics/high-school/huajia6j53ws5spc748zvwoyid1i9duv2i.png)
![\displaystyle v=420\cdot\sqrt{\frac {9.8}{420}}](https://img.qammunity.org/2021/formulas/physics/high-school/1hr4a0eaqou9dr9nwvp9rpo8p9cnkkwt8c.png)
v = 64.16 m/s
His initial velocity (speed) must be 64.16 m/s.