Answer: pretty sure it’s B and C hope it helps ✨
Step-by-step explanation: ax2+bx+c=0 a[(x+b/2a)2-b2/4a2+c/a]=0 (x+b/2a)2=(b2-4ac)/4a2 x=[-b±√(b2-4ac)]/2a
5.1m questions
6.7m answers