Question

620 mL of nitrogen at standard pressure is compressed into a 480 mL container. What is the new pressure in kPa?

a. 982 kPa
b. 1.29 kPa
c. 131 kPa
d. 78.4 kPa

Answer 1

c. 131 kPa

Step-by-step explanation:

Hello!

In this case, since the relationship between volume and pressure is inversely proportional, based on the Boyle's law:

`P_1V_1=P_2V_2`

Considering that the standard pressure is 101.325 kPa, we can compute the final pressure as shown below:

`P_2=(P_1V_1)/(V_2)=(620mL*101.325kPa)/(480mL)\\\\P_2=131kPa`

Therefore, the answer is c. 131 kPa .

Best regards!!