Question

How to solve for axis of symmetry for y=(x+2)(x-4)

Answer 1

x=1

Explanation:

`y=x^(2) -4x+2x-8`

`y=x^(2) -2x-8`
`(a=1, b=-2)`

`x=-(b)/(2a) =(-2)/(2*1)`

`x=1`

`y=(x+2)(x-4), x=1`

`y=(1+2)(1-4)`

`y=-9`

Answer 2

x = 1

Explanation:

you can first find the two zeroes

that would be

x + 2 = 0

x - 4 = 0

x = {-2, 4}

then you average them

-2 + 4 = 2

2 / 2 = 1

the aos is 1