Question

*please help me out if you know how to solve, last person I asked just put a random awnser for point, the problem is bellow and there is a chart in the picture.*

6. In both Mr. Jacquez's Math 2 classes,
Period 2 and Period 3 were given the same test. The table below shows the results from the two classes.

a. Find the probability that a randomly selected student from Period 2's class failed the test.

b. Find the probability that a randomly selected student who failed the test is from Period 3's class​

Answer 1

For both of these, we will divide the wanted outcome by the number of possible outcomes. We will end up with a decimal. A decimal multiplied by 100 becomes a percent.

[a] 50%

`\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed}}{\text{Period 2's class}} =(12)/(24) =0.5,\:0.5*100=50\%`

[b] 52%

`\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed from Period 3}}{\text{fails from both classes}} =(13)/(25) =0.52,`

`\displaystyle 0.52*100=52\%`