Question

What product(s) are formed during this chemical reaction? (Will be two answers)

B(NO3)3 + KBr rightwards arrow


K(Br)3


KNO3


Br3(NO3)2


K3NO4


B(NO3)K


B3K3


BBr3


BK

Answer 1

During the chemical reaction between B(NO3)3 and KBr, the products formed are potassium nitrate (KNO3) and boron tribromide (BBr3).

Step-by-step explanation:

The reaction between B(NO3)3 (boron nitrate) and KBr (potassium bromide) is a double displacement reaction. When we swap the anions and cations of the reactants, we expect the formation of potassium nitrate (KNO3) and boron tribromide (BBr3). Therefore, the chemical equation for this reaction is:

B(NO3)3 (aq) + 3 KBr (aq) → 3 KNO3 (aq) + BBr3 (s)

This equation is balanced as written, with a stoichiometry of one molecule of B(NO3)3 reacting with three molecules of KBr to form three molecules of KNO3 and one molecule of BBr3. The products of this reaction are potassium nitrate and boron tribromide.