2.6k views
3 votes
Determine the solution for x^2-3x-28=\> 0

User SRandazzo
by
6.6k points

2 Answers

2 votes

Answer:

(infinity, -4] or [7, infinity).

Explanation:

right on edge

User Chola
by
6.5k points
4 votes

Answer: x = -4 or x = 7

Explanation:

x^2 - 3x - 28 =/>

(factor)

(x^2 + 4)(x-7) = 0

x + 4 = 0 or x - 7 = 0

(subtract -4 from 0 and 7 from 0)

x = -4 or x =7

User Aerus
by
6.4k points
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