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5 votes
2,11,20 find the t15

User Michahell
by
8.4k points

1 Answer

3 votes

Answer:

128

Explanation:

There is a common difference between consecutive terms, that is

11 - 2 = 20 - 11 = 9

This indicates the sequence is arithmetic with n th term


t_(n) = t₁ + (n - 1)d

where t₁ is the first term and d the common difference

Here t₁ = 2 and d = 9 , thus

t₁₅ = 2 + (14 × 9) = 2 + 126 = 128

User Zap
by
8.9k points

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