Answer:
The three integers are 12,13 and 14
Explanation:
Let
x,x+1,x+2 be three consecutive integers.
Out of these, the smallest one is x and largest is x+2 as it comes at last in the integers.
So according to given statement

This is a linear equation in one variable, which can simply be solved by using equality properties

Subtracting 4x from both sides

Subtracting 3 from both sides

The smallest integer is 12.
The other integers are:
x+1 = 12+1 = 13
x+2 = 12+2 = 14
Hence,
The three integers are 12,13 and 14