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Find 3 consecutive integers such that the sum of all 3 integers is equal to 4 times the smallest integer minus 9. Please help I need it asap I will appreciate it a lotttt

User Mwallisch
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1 Answer

2 votes

Answer:

The three integers are 12,13 and 14

Explanation:

Let

x,x+1,x+2 be three consecutive integers.

Out of these, the smallest one is x and largest is x+2 as it comes at last in the integers.

So according to given statement


x+(x+1)+(x+2) = 4x-9

This is a linear equation in one variable, which can simply be solved by using equality properties


x+x+1+x+2 = 4x-9\\3x+3 = 4x-9

Subtracting 4x from both sides


3x+3-4x = 4x-9-4x\\-x+3=-9

Subtracting 3 from both sides


-x+3-3 = -9-3\\-x = -12\\x = 12

The smallest integer is 12.

The other integers are:

x+1 = 12+1 = 13

x+2 = 12+2 = 14

Hence,

The three integers are 12,13 and 14

User Nashla
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