The equation of the line in point-slope form, passing through (0, 6) with a slope of 3/4, is
. Simplifying, it becomes
.
The point-slope form of the equation of a line is given by:
![\[ y - y_1 = m(x - x_1) \]](https://img.qammunity.org/2021/formulas/mathematics/middle-school/q63fbhqii6pllg76ls82xufftnsy24ascb.png)
where
is a point on the line, and m is the slope.
In this case, the point is (0, 6), and the slope is 3/4. Plugging these values into the point-slope form:
![\[ y - 6 = (3)/(4)(x - 0) \]](https://img.qammunity.org/2021/formulas/mathematics/college/bkusenm8ko2i8ro0bqf4kg94uuotvjsw8s.png)
Simplifying:
![\[ y - 6 = (3)/(4)x \]](https://img.qammunity.org/2021/formulas/mathematics/college/qk8mx8x2qzloi92gnn4zb7yykq1d45jtav.png)
This is the equation of the line in point-slope form. If you want to express it in slope-intercept form y = mx + b, you can further simplify:
![\[ y = (3)/(4)x + 6 \]](https://img.qammunity.org/2021/formulas/mathematics/college/btjx83lfz8fs37bzalls5biajofzjll8hm.png)
The complete question is:
What is the equation of the line (in point-slope form) that passes through the point (0, 6) and has a slope of 3/4?