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Slope = 3/4 , goes through the point (0, 6)

User Dirkgently
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2 Answers

2 votes

Answer:

y = 3/4x + 6

Explanation:

User Shintaroid
by
8.3k points
1 vote

The equation of the line in point-slope form, passing through (0, 6) with a slope of 3/4, is
\(y - 6 = (3)/(4)x\). Simplifying, it becomes
\(y = (3)/(4)x + 6\).

The point-slope form of the equation of a line is given by:


\[ y - y_1 = m(x - x_1) \]

where
\((x_1, y_1)\) is a point on the line, and m is the slope.

In this case, the point is (0, 6), and the slope is 3/4. Plugging these values into the point-slope form:


\[ y - 6 = (3)/(4)(x - 0) \]

Simplifying:


\[ y - 6 = (3)/(4)x \]

This is the equation of the line in point-slope form. If you want to express it in slope-intercept form y = mx + b, you can further simplify:


\[ y = (3)/(4)x + 6 \]

The complete question is:

What is the equation of the line (in point-slope form) that passes through the point (0, 6) and has a slope of 3/4?

User Nitin Kumar
by
8.4k points

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