Question

How do I find y to solve for the vertex? (Transformations, Quadratic functions)

I know how to solve for the x but I'm confused on solving for the Y. Thank you!

Answer 1

the other answer is zero.

Explanation:

Step 1: Use the vertex form,
`y=a(x-h)^2+k`, to determine the values of a, h, and k. The "k" value is always the "y" value in a ordered pair. Since there is no "k" value, the "k" value will just be zero. In turn, since the "k" value is zero... so will the "y" value be zero.

`a=8\\\\h=21\\\\k=0`