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How much heat is required to raise the temperature of a 6.21 g sample of iron from 25.0 oC to 79.8 oC?

1 Answer

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Answer:

151.1J

Step-by-step explanation:

Given parameters:

Mass of iron = 6.21g

Initial temperature of iron = 25°C

Final temperature of iron = 79.8°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat require to cause this temperature can be determined using the expression below;

H = m c (T₂ - T₁)

H is the amount of heat

m is the mass

c is the specific heat capacity

T is the temperature

Specific heat capacity of iron 0.444J/g°C

Insert the parameters and solve;

H = 6.21 x 0.444 x (79.8 - 25)

H = 151.1J

User Nicolas Caous
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