If sin t = -8/17 and t is a quadrant III angle, find cot t

Question

asked Oct 21, 2021 230k views

1 Answer

SiliconMind · Answer 1 · 2021-10-27T17:51:08+0000

Answer:cot t = 1.875

sin t=(-8)/(17) but sin²t + cos²t = 1 ⇔ cos²t = 1 - sin²t

⇔cos t =
$\sqrt{1-sin^(2)t }=\sqrt{1-((-8)/(17))^(2) }=|(15)/(17)|$

but t is a quadrant III angle => cos t =
(-15)/(17)

=> cot t =
(-15)/(17):(-8)/(17)=(15)/(8)=1.875

Explanation: