Question

Find the values of a,b and c

Answer 1

`a= -\frac 23\\\\ b = -8\\\\ c = -47`

Explanation:

`b(x) = -\frac 23(x+6)^2 -23\\\\\\~~~~~~=-\frac 23(x^2 +2\cdot 6 \cdot x +6^2) -23\\\\\\~~~~~~=-\frac 23(x^2 +12x +36) -23\\\\\\~~~~~~=-\frac 23 x^2 - \frac{24}3 x - (72)/(3)-23\\\\\\~~~~~~=-\frac 23 x^2 -8x-24-23\\\\\\~~~~~~=-\frac 23x^2 -8x -47\\\\\text{By comparing}~ -\frac 23x^2 -8x -47~\text{with the standard form, }~ ax^2 +bx +c,\\\\a= -\frac 23,~ b = -8~ \text{and}~ c = -47`