Question

How much heat energy is needed to raise the temperature of 135 g of water (specific heat of water = 4.19 J/g-C) from 15 degrees Celsius to 27 degrees Celsius?

Answer 1

Required heat = 6,787.8 j (Approx)

Step-by-step explanation:

Given:

Mass of water = 135 g = 0.135 g

Specific heat of water = 4.19 J/g-C

Change in temperature = 27 - 15 = 12 degrees Celsius

Find:

Required heat

Computation:

Required heat = mcΔt

Required heat = (135)(4.19)(12)

Required heat = 6,787.8 j (Approx)