3x^2+8x+4=0 Solve using the quadratic formula.

Question

`3x^2+8x+4=0`
Solve using the quadratic formula.

Answer 1

`x = -\frac 23\\\\x = -2`

Step by step explanation:

`3x^2 +8x +4 =0\\\\\text{The quadratic formula,}~ x = (-b\pm√(b^2 -4ac))/(2a).\\\\\text{By comparing}~ 3x^2 +8x +4~ \text{with the standard form}~ ax^2 +bx +c,\\\\a = 3, ~b = 8 ,~ c = 4\\\\\text{Now,}~\\\\x = (-8\pm√(8^2 -4 * 3 * 4))/(2(3))\\\\\\~~~=(-8\pm√(64-48))/(6)\\\\\\~~~=(-8\pm√(16))/(6)\\\\\\~~~=(-8\pm 4 )/(6)\\`

`x = (-8+4)/(6)=-(4)/(6)= -\frac 23\\\\x= (-8-4)/(6)= -(12)/(6)=-2`