Answer:
D.
Explanation:
From the figure, we have
The coordinates of the point F are: (-4,1).
The coordinates of the point G are: (0,-2)
The coordinates of the point J are: (0,4) and
The coordinates of the point H are: (-4,-2).
Now, the slope of the line FG is :
S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}S=
x
2
−x
1
y
2
−y
1
S=\frac{-2-1}{0+4}S=
0+4
−2−1
S=\frac{-3}{4}S=
4
−3
And, the slope of the line HJ is:
S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}S=
x
2
−x
1
y
2
−y
1
S=\frac{-2-4}{-4-0}S=
−4−0
−2−4
S=\frac{3}{2}S=
2
3
Now, the slope of FG=\frac{1}{slope of HJ}theslopeofFG=
slopeofHJ
1
\frac{-3}{4}=\frac{2}{3}
4
−3
=
3
2
which is not possible, thus They are not perpendicular because their slopes are not negative reciprocals.