Question

Prasitha has two buildings A and B. A is 10 feet shorter than the twice the height of B. The distance between the buildings is 120 feet and the height of B is 60 feet. Find the distance between their tops.

Answer 1

The distance between their tops is 130 feet

Explanation:

The given parameters are;

The height of A,
`h_A` = 2 × The height of B - 10

The distance between the two buildings, d = 120 feet

The height of B,
`h_B` = 60 feet

Therefore, we have;

The height of A,
`h_A` = 2 × The height of B - 10 = 2 × 60 - 10 = 110 feet

The height of A,
`h_A` = 110 feet

By Pythagoras theorem, the distance between their tops = √((
`h_A` -
`h_B`)² + d²)

Substituting the values gives;

The distance between their tops = √((110 - 60)² + 120²) = 130

The distance between their tops = 130 feet.