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5 votes
Use quadratic formula to solve 1-6x^2-x​

1 Answer

3 votes

Answer:

(3x-1)(2x+1)

Explanation:

1-6x^2-x=0

-6x^2-x+1=0

6x^2+x-1=0

6x^2+(3-2)x-1=0

6x^2+3x-2x-1=0

3x(2x+1)-1(2x+1)=0

(3x-1)(2x+1)=0

So the factor is (3x-1)(2x+1)

User Teiem
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