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Someone help plz. quick. :/

Someone help plz. quick. :/-example-1
User AhmedWas
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1 Answer

1 vote

Answer:

y = 2x - 22

Explanation:

y = 2x - 8

it is the form of y = mx + c

to be parallel the m should be the same ..

so the equation m = 2

znd it is given that it is passing (11,0) so that the equation should satisfy the point ( 11,0)

y = mx + c

y = 0 , m = 2 , x = 11

0 = 2 ( 11 ) + c

c = -22

so the required equation for the parallel line is

y = 2x - 22

User Earl Mascetti
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