Question

PLEASE, I NEED HELP FAST!

n²-4-n-2 is equal to
A) (n-2)n
B) (n-2)(n+1)
C) (n+2)(n-3)
D) (n+2)n

And please write good explanation, not only the answer. Thank you!​

Answer 1

n^2-4-n-2

First, you need to combine like terms. (-2)+(-4)= -6

n^2-n-6

To factor, find two numbers that multiply to make -6, and add to make -1 (the coefficient of the n).

These numbers are -3, and 2, since (-3)+2= -1, and (-3)(2)=-6.

to get n^2, you need to multiply n x n.

Therefore, in one of your parenthesis will be (n+2), and the other will be (n-3).

To check, you can always multiply these back out.

(n+2)(n-3)

First, do n times n, which is n^2. Next, do n (first n) times -3, which is -3n. Then, do 2 times n (second n), which gives you 2n. Finally, multiply 2 and -3, which gives you -6.

Combine the like terms, and this gives you
n^2-n-6

Therefore, your answer is C

I hope this helped!! If you need any more explanation feel free to comment on my answer and I’ll get back to you ASAP. :)