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What is the normal force acting on the 7.50 kg box shown?
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What is the normal force acting on the 7.50 kg box shown?

What is the normal force acting on the 7.50 kg box shown?-example-1
User Josh Powlison
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The answer would be 31 N. This is because Fn = 7.5*9.8*sin(25).

User Mehdi Chennoufi
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