Question

If a man with a mass of 75 kg, standing still, throws an object with a mass of 5 kg at 30 m/s, what will be the recoil velocity of the man, assuming he is standing on a frictionless surface?

Answer 1

2 m/s

Step-by-step explanation:

Given that,

Mass of a man, m₁ = 75 kg

Mass of object, m₂ = 5 kg

Velocity of the object, v₂ = 30 m/s

We need to find the recoil velocity of the man. Let it is v₁. In the whole process, the momentum of the system will remain conserved such that,

`m_1v_1=m_2v_2\\\\v_1=(m_2v_2)/(m_1)\\\\v_1=(5* 30)/(75)\\\\v_1=2\ m/s`

So, the recoil velocity of the man is 2 m/s