Question

Can any kind soul help me please​

Answer 1

Step-by-step explanation:

Hey there!

Given;

Mass of the Earth (M) = 6.0*10^24kg.

Radius of Earth (R) = 6400km = 6400*1000= 6.4*10^6.

Gravitational constant (G) = 6.67*10^-11Nm^2/kg^2.

Height from surface of Earth (h) = 350km= 3.5*10^5m

Gravity (g) = ?

We have;

`g = \frac{G.M}{ {(R + h)}^(2) }`

Where "G" is gravitational constant, "M" is mass of earth, "g" is acceleration due to gravity, "h" height from surface of Earth.

Keep all values.

`g = \frac{6.67 * {10}^( - 11) * 6.0 * {10}^(24) }{ (6.4 * {10}^(6) + 3.5 * {10}^(5) )^2}`

`or \: g = \frac{40.002* {10}^(13) }{ (6.4* {10}^(6) + 3.5*10^5)^2}`

g = 8.7m/s^2

Therefore, gravity from distance 350km above the Earth's surface is 8.7m/s^2.

Hope it helps...