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A car leaving A stop sign accelerates constantly from a speed of 0 ft./s to reach a speed of 44 ft./s. The distance of the car from the stop sign, d, in feet, at a time t, in seconds, can be found using the equation d=1.1t to the second power.

What is the average speed of the car, in feet per second, between t=2 and t=5

1 Answer

7 votes
I got 7.7 , I’m not sure
User Theomax
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