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How many atoms are in 80.7 g of pure aluminum?​

User Eulerdisk
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1 Answer

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Answer:

Like Roman said Avogadro's number is the key to your problem. The value that you'll use on paper is 6.022x10^23. Luckily in our case a mol specifically refers to the amount of atoms. Its a weird concept but 1.97 mol of Aluminum is the exact same amount of atoms as say helium. The only differences lay in the total mass of the sample.

User Gmetax
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