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A student kicks a soccer ball upward at a 30º angle with an initial speed of 20 m∕s. What expression should the student use to calculate the magnitude of the ball’s initial velocity in the horizontal direction?

User TamilKing
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1 Answer

6 votes

Answer:


\displaystyle x=10√(3)\ m/s


y=10\ m/s

Step-by-step explanation:

Rectangular coordinates of vectors in 2D

Given a vector with a magnitude v and angle θ with respect to the positive horizontal direction, the x and y components of the vector are given by:


x=v\cos\theta


y=v\sin\theta

The soccer ball is kicked upward at an angle θ = 30° and at a speed v=20 m/s.

The rectangular components of the vector are:


x=20\cos 30^\circ


\displaystyle x=20\cdot (√(3))/(2)

Operating:


\mathbf{\displaystyle x=10√(3)\ m/s}


y=20\sin 30^\circ


\displaystyle y=20\cdot (1)/(2)

Operating:


\mathbf{y=10\ m/s}

User Raphael Sauer
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