Question

A motorcyclist drives around a bend with a 20 m radius, with a constant velocity of 3 m/s. The motorcyclist and the motorcycle have a combined mass of 50 kg. What is the motorcyclist’s centripetal acceleration?

Answer 1

`a=0.45\ m/s^2`

Step-by-step explanation:

Given that,

The radius of a bend, r = 20 m

Velocity of motorcyclist, v = 3 m/s

The combined mass of motorcyclist and the motorcycle is 50 kg

We need to find the motorcyclist’s centripetal acceleration. The formula used to find the centripetal acceleration is given by :

`a=(v^2)/(r)\\\\a=((3)^2)/(20)\\\\a=0.45\ m/s^2`

So, the acceleration of the motorcyclist is
`0.45\ m/s^2`.