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For the reaction: Agl(s) + V2Br2(g) AgBr(s) + /12 () AH° = -54.0 kJ And: AH® for AgBr(s) = -100.4 kJ/mol AH° for Br2(g) = +30.9 kJ/mol Therefore value of AH for Agl(s) must be: +61.8 kJ/mol. -61.8 kJ/mol.
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3 votes
For the reaction:

Agl(s) + V2Br2(g) AgBr(s) + /12 ()
AH° = -54.0 kJ
And:
AH® for AgBr(s) = -100.4 kJ/mol
AH° for Br2(g) = +30.9 kJ/mol
Therefore value of AH for Agl(s) must be:
+61.8 kJ/mol.
-61.8 kJ/mol.
O-123.5 kJ/mol.
+77.3 kJ/mol.
O-77.3 kJ/mol.

User Quispie
by
7.0k points

1 Answer

3 votes

Answer:

0-77.3kj/mol

Step-by-step explanation:

add all of the mole

User Omer Greenwald
by
7.4k points
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